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1967 CONCACAF Championship qualification

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For the 1967 CONCACAF Championship, a total of 10 teams entered the competition.  Honduras, as the hosts, and  Mexico, as the defending champions, qualified automatically, leaving 4 spots open for competition. The 8 teams were divided into 2 groups in which the top 2 in each group advanced to the final tournament.

Group 1

Played in Kingston, Jamaica.

The group was also referred to as the Red Stripe Trophy within Jamaica. The group was sponsored by Desnoes & Geddes, the brewery of Red Stripe beer.[1]

Pos Team Pld W D L GF GA GD Pts
1  Haiti 4 3 1 0 7 3 +4 7
2  Trinidad and Tobago 4 2 1 1 7 7 0 5
3  Jamaica 4 1 2 1 4 4 0 4
4  Cuba 4 0 2 2 5 7 −2 2
5  Netherlands Antilles 4 0 2 2 4 6 −2 2
Jamaica 1–1 Netherlands Antilles

Cuba 1–1 Haiti

Trinidad and Tobago 2–1 Netherlands Antilles
Small Goal 75'
Archibald Goal 76'
Perez Goal (pen)

Jamaica 2–1 Cuba

Haiti 4–2 Trinidad and Tobago
Corneal Goal 37' (pen.)
Archibald Goal 65'

Netherlands Antilles 2–2 Cuba
Dirks Goal
Perez Goal
Hernandez Goal
Mico Goal

Jamaica 1–1 Trinidad and Tobago
Archibald Goal 49'

Haiti 1–0 Netherlands Antilles

Trinidad and Tobago 2–1 Cuba
Archibald Goal 11'
Aleong Goal 15'

Jamaica 0–1 Haiti

Haiti and Trinidad and Tobago qualified for the final tournament.

Group 2

Played in Ciudad de Guatemala, Guatemala.

Pos Team Pld W D L GF GA GD Pts
1  Guatemala 2 2 0 0 6 2 +4 4
2  Nicaragua 2 1 0 1 4 4 0 2
3  Panama 2 0 0 2 2 6 −4 0
Guatemala 3–1 Panama

Guatemala 3–1 Nicaragua

Panama 1–3 Nicaragua

Guatemala and Nicaragua qualified for the final tournament.

References

  1. ^ "Haitian goalkeeper suspended". Kingston Gleaner. 23 January 1967. p. 28.
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1967 CONCACAF Championship qualification
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