Pleasanton, Iowa
City in Iowa, United States / From Wikipedia, the free encyclopedia
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Pleasanton is a city in Decatur County, Iowa, United States. The population was 32 at the time of the 2020 census.[3]
Quick Facts Country, State ...
Pleasanton, Iowa | |
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Coordinates: 40°34′57″N 93°44′35″W | |
Country | United States |
State | Iowa |
County | Decatur |
Area | |
• Total | 0.35 sq mi (0.91 km2) |
• Land | 0.35 sq mi (0.91 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 1,099 ft (335 m) |
Population (2020) | |
• Total | 32 |
• Density | 91.17/sq mi (35.21/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP code | 50065/50224 |
Area code | 641 |
FIPS code | 19-63570 |
GNIS feature ID | 2396235[2] |
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