Sędzin
Village in Kuyavian-Pomeranian Voivodeship, Poland / From Wikipedia, the free encyclopedia
Sędzin [ˈsɛnd͡ʑin] is a village in the administrative district of Gmina Zakrzewo, within Aleksandrów County, Kuyavian-Pomeranian Voivodeship, in north-central Poland.[1] It lies 18 kilometres (11 mi) south-west of Aleksandrów Kujawski and 34 km (21 mi) south of Toruń. It is located in Kuyavia.
Quick Facts Country, Voivodeship ...
Sędzin | |
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Village | |
Coordinates: 52°44′N 18°34′E | |
Country | Poland |
Voivodeship | Kuyavian-Pomeranian |
County | Aleksandrów |
Gmina | Zakrzewo |
Population (approx.) | 600 |
Time zone | UTC+1 (CET) |
• Summer (DST) | UTC+2 (CEST) |
Vehicle registration | CAL |
Voivodeship roads |
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The village has an approximate population of 600.