2018 United States Senate election in Wyoming
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The 2018 United States Senate election in Wyoming took place on November 6, 2018 to elect a member of the United States Senate to represent the State of Wyoming. The primary election took place August 21, 2018.[1] Republican John Barrasso won re-election with 67% percent of the vote, the lowest percentage of his three U.S. Senate campaigns and the closest a Democrat has came to winning a seat since the 1996 election, and the first time since that election in which Democrats managed to even win counties in the state, those being Teton and Albany, and the first time that the Democratic candidate won any counties for this seat since 1994.
For related races, see 2018 United States Senate elections.
Quick Facts Turnout, Nominee ...
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Turnout | 77.43% | ||||||||||||||||
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Barrasso: 40–50% 50–60% 60–70% 70–80% 80–90% >90% Trauner: 40–50% 50–60% 60–70% 70–80% No votes | |||||||||||||||||
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