Calapooia River
River in Oregon, United States of America / From Wikipedia, the free encyclopedia
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The Calapooia River is an 80-mile (130 km) tributary of the Willamette River in the U.S. state of Oregon.[4]
Calapooia River | |
---|---|
Etymology | For the Kalapuya people of the Willamette Valley[1] |
Location | |
Country | United States |
State | Oregon |
County | Linn |
Physical characteristics | |
Source | Cascade Range |
• coordinates | 44°15′54″N 122°19′25″W[2] |
• elevation | 4,552 ft (1,387 m)[3] |
Mouth | Willamette River |
• coordinates | 44°38′20″N 123°6′36″W[2] |
• elevation | 180 ft (55 m)[2] |
Length | 80 mi (130 km)[4] |
Basin size | 374 sq mi (970 km2)[4] |
Discharge | |
• average | 898 cu ft/s (25.4 m3/s)[4] |
The Calapooia flows generally northwest from its source in the Cascade Range near Tidbits Mountain. In its upper reaches, it passes through parts of the Willamette National Forest. Further downstream, it flows through Holley then Crawfordsville and Brownsville in the Willamette Valley before joining the Willamette at Albany. The city of Tangent is also near the river on a branch of one of its downstream tributaries, Lake Creek. The confluence of the two rivers is about 120 miles (190 km) by water from where the Willamette joins the Columbia River[5]
The Calapooia was named for the Kalapuya (also spelled Calapooia), a tribe of Native Americans.[1]