Frankfort, Indiana
City in Indiana, United States / From Wikipedia, the free encyclopedia
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Frankfort is a city in Clinton County, Indiana, United States. It had a population of 16,715 as of the 2020 census. The city is the county seat of Clinton County.[4]
Quick Facts Country, State ...
Frankfort, Indiana | |
---|---|
Coordinates: 40°16′47″N 86°30′21″W | |
Country | United States |
State | Indiana |
County | Clinton |
Township | Center |
Founded | 1830 |
Incorporated | 1846 |
Named for | Frankfurt am Main |
Government | |
• Mayor | Judith Sheets (R) |
Area | |
• Total | 8.05 sq mi (20.86 km2) |
• Land | 8.05 sq mi (20.86 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 860 ft (260 m) |
Population (2020) | |
• Total | 16,715 |
• Density | 2,075.11/sq mi (801.21/km2) |
Time zone | UTC-5 (EST) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 46041 |
Area code | 765 |
FIPS code | 18-25324[3] |
GNIS feature ID | 2394805[2] |
Website | frankfort-in.gov |
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