Julia Glushko
Israeli tennis player (born 1990) / From Wikipedia, the free encyclopedia
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Julia Glushko (or Yulia,[2] Hebrew: יוליה גלושקו; born 4 January 1990) is an Israeli former tennis player.
Full name | Julia Glushko |
---|---|
Country (sports) | Israel |
Residence | Modi'in, Israel |
Born | (1990-01-01) 1 January 1990 (age 34) Donetsk, Ukrainian SSR, USSR |
Height | 1.71 m (5 ft 7 in)[1] |
Turned pro | 2005 |
Retired | 2019 |
Plays | Right-handed (two-handed backhand) |
Prize money | $998,044 |
Singles | |
Career record | 388–320 (54.8%) |
Career titles | 11 ITF |
Highest ranking | No. 79 (23 June 2014) |
Grand Slam singles results | |
Australian Open | 1R (2014) |
French Open | 3R (2014) |
Wimbledon | 1R (2014) |
US Open | 3R (2013) |
Doubles | |
Career record | 182–165 (52.4%) |
Career titles | 14 ITF |
Highest ranking | No. 109 (4 November 2013) |
Grand Slam doubles results | |
Wimbledon | Q1 (2013) |
Team competitions | |
Fed Cup | 29–29 |
She won 11 singles and 14 doubles titles on the ITF Circuit.[3] Her best results at a Grand Slam tournament were reaching the third round of the US Open in 2013, and the French Open in 2014 in singles.[3] In September 2015, she reached the final of the WTA Challenger event in Dalian, where she was defeated by Zheng Saisai.[4]
On 23 June 2014, Glushko reached her best singles ranking of world No. 79. On 4 November 2013, she peaked at No. 109 in the doubles rankings. She won the 2011 Israeli National Women's Singles Championship. Playing for Israel in the Fed Cup, she had a win–loss record of 29–29.[3]